16x^2+50x=-25

Solution for 16x^2+50x=-25 equation:

16x^2+50x=-25

We move all terms to the left:

16x^2+50x-(-25)=0

We add all the numbers together, and all the variables

16x^2+50x+25=0

a = 16; b = 50; c = +25;
Δ = b2-4ac
Δ = 502-4·16·25
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-30}{2*16}=\frac{-80}{32}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+30}{2*16}=\frac{-20}{32}
=-5/8
$